![Harder Series Solution Differential Equation y'' - 2xy' + 8y = 0 with Initial Conditions | Differential equations, Math videos, Solutions Harder Series Solution Differential Equation y'' - 2xy' + 8y = 0 with Initial Conditions | Differential equations, Math videos, Solutions](https://i.pinimg.com/originals/aa/a6/e3/aaa6e3a1d866fb12aabdb1a4f2c97a02.jpg)
Harder Series Solution Differential Equation y'' - 2xy' + 8y = 0 with Initial Conditions | Differential equations, Math videos, Solutions
![ordinary differential equations - Power series solution to $y' + 2xy = 0$ - Mathematics Stack Exchange ordinary differential equations - Power series solution to $y' + 2xy = 0$ - Mathematics Stack Exchange](https://i.stack.imgur.com/gEr18.png)
ordinary differential equations - Power series solution to $y' + 2xy = 0$ - Mathematics Stack Exchange
![SOLVED: Find the integrating factor for the non-exact differential equations: 2xy dx + (y2 3x 2)dy = 0 A) 4=y + B) 4=-y"4 C) p = %y D) 4=-Zy SOLVED: Find the integrating factor for the non-exact differential equations: 2xy dx + (y2 3x 2)dy = 0 A) 4=y + B) 4=-y"4 C) p = %y D) 4=-Zy](https://cdn.numerade.com/ask_images/fbe1b935aeb0424bbec337756e02ba68.jpg)
SOLVED: Find the integrating factor for the non-exact differential equations: 2xy dx + (y2 3x 2)dy = 0 A) 4=y + B) 4=-y"4 C) p = %y D) 4=-Zy
![SOLVED: (1 point) Find two linearly independent solutions of y' + 2xy = 0 of the form Y1 = 1+a3x + dx6 + Y2 =x+b4x4 + box7 + Enter the first few coefficients: 03 @6 b4 = b7 SOLVED: (1 point) Find two linearly independent solutions of y' + 2xy = 0 of the form Y1 = 1+a3x + dx6 + Y2 =x+b4x4 + box7 + Enter the first few coefficients: 03 @6 b4 = b7](https://cdn.numerade.com/ask_images/9317bb756b3649ea894cf81d9e80da89.jpg)