![An AC is given by the equation `i=i_(1)cos omegat+i_(2)sin omegat`. The r.m.s. current is given by - YouTube An AC is given by the equation `i=i_(1)cos omegat+i_(2)sin omegat`. The r.m.s. current is given by - YouTube](https://i.ytimg.com/vi/MJrgJfC65BA/maxresdefault.jpg)
An AC is given by the equation `i=i_(1)cos omegat+i_(2)sin omegat`. The r.m.s. current is given by - YouTube
![Question Video: Finding the Cosine of Angles in Right-Angled Triangles given the Opposite Side and the Hypotenuse | Nagwa Question Video: Finding the Cosine of Angles in Right-Angled Triangles given the Opposite Side and the Hypotenuse | Nagwa](https://media.nagwa.com/758153127354/en/thumbnail_l.jpeg)
Question Video: Finding the Cosine of Angles in Right-Angled Triangles given the Opposite Side and the Hypotenuse | Nagwa
![What equation can be used to find the length of AC(10)sin(40°)=AC(10)cos (40°)=AC10/sin(40°)=AC10/cos - Brainly.com What equation can be used to find the length of AC(10)sin(40°)=AC(10)cos (40°)=AC10/sin(40°)=AC10/cos - Brainly.com](https://us-static.z-dn.net/files/dab/3aca364f11c91b794c25632199f5d4ca.jpg)
What equation can be used to find the length of AC(10)sin(40°)=AC(10)cos (40°)=AC10/sin(40°)=AC10/cos - Brainly.com
![In triangle ABC, angle C is a right angle and AC = 8, BC = 15, and AB = 17. Find 1. angle A and angle B 2. sine A 3. cos A 4. sin B 5. cos B | Homework.Study.com In triangle ABC, angle C is a right angle and AC = 8, BC = 15, and AB = 17. Find 1. angle A and angle B 2. sine A 3. cos A 4. sin B 5. cos B | Homework.Study.com](https://homework.study.com/cimages/multimages/16/geogebra-export-177725909481221221388.png)
In triangle ABC, angle C is a right angle and AC = 8, BC = 15, and AB = 17. Find 1. angle A and angle B 2. sine A 3. cos A 4. sin B 5. cos B | Homework.Study.com
![trigonometry - ABC is a triangle. D is the center of BC . AC is perpendicular to AD. prove that $\cos(A)\cdot \cos(C)=\frac{2(c^2-a^2)}{3ac}$ - Mathematics Stack Exchange trigonometry - ABC is a triangle. D is the center of BC . AC is perpendicular to AD. prove that $\cos(A)\cdot \cos(C)=\frac{2(c^2-a^2)}{3ac}$ - Mathematics Stack Exchange](https://i.stack.imgur.com/G2iqr.jpg)
trigonometry - ABC is a triangle. D is the center of BC . AC is perpendicular to AD. prove that $\cos(A)\cdot \cos(C)=\frac{2(c^2-a^2)}{3ac}$ - Mathematics Stack Exchange
![prove using sine rule 1+cos(A-B) cos C / 1+cos(A-C) cos B = a2+ b2/ a2- c2 - Maths - Trigonometric Functions - 2522056 | Meritnation.com prove using sine rule 1+cos(A-B) cos C / 1+cos(A-C) cos B = a2+ b2/ a2- c2 - Maths - Trigonometric Functions - 2522056 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/discuss_editlive/2569807/2012_06_19_11_51_28/mathmlequation7490107235482424758.png)
prove using sine rule 1+cos(A-B) cos C / 1+cos(A-C) cos B = a2+ b2/ a2- c2 - Maths - Trigonometric Functions - 2522056 | Meritnation.com
![geometry - In $\triangle ABC$, if $AC=4$ and $BC=5$, and $\cos(A-B)=\frac{7}{8}$, find $\cos(C)$ - Mathematics Stack Exchange geometry - In $\triangle ABC$, if $AC=4$ and $BC=5$, and $\cos(A-B)=\frac{7}{8}$, find $\cos(C)$ - Mathematics Stack Exchange](https://i.stack.imgur.com/nZbSU.png)
geometry - In $\triangle ABC$, if $AC=4$ and $BC=5$, and $\cos(A-B)=\frac{7}{8}$, find $\cos(C)$ - Mathematics Stack Exchange
![SOLVED: In ΔABC, m∠B = 90°, cos(C) = 15/17 , and AB = 16 units. Based on this information, m∠A = °, m∠C = °, and AC = units. Note that the SOLVED: In ΔABC, m∠B = 90°, cos(C) = 15/17 , and AB = 16 units. Based on this information, m∠A = °, m∠C = °, and AC = units. Note that the](https://cdn.numerade.com/ask_previews/f74cbc56-8e21-4c20-9d8c-c8e51ebb001c_large.jpg)
SOLVED: In ΔABC, m∠B = 90°, cos(C) = 15/17 , and AB = 16 units. Based on this information, m∠A = °, m∠C = °, and AC = units. Note that the
![One-pot synthesis of a CoS-AC electrode in a redox electrolyte for high-performance supercapacitors | SpringerLink One-pot synthesis of a CoS-AC electrode in a redox electrolyte for high-performance supercapacitors | SpringerLink](https://media.springernature.com/lw685/springer-static/image/art%3A10.1007%2Fs10800-019-01341-y/MediaObjects/10800_2019_1341_Figa_HTML.png)
One-pot synthesis of a CoS-AC electrode in a redox electrolyte for high-performance supercapacitors | SpringerLink
![Elements of plane and spherical trigonometry . le, Fig. 21, BD = AB — AD, and in the second, BD = AD — AB;but in both cases BD2 = AB2 + Elements of plane and spherical trigonometry . le, Fig. 21, BD = AB — AD, and in the second, BD = AD — AB;but in both cases BD2 = AB2 +](https://c8.alamy.com/comp/2CE0H3A/elements-of-plane-and-spherical-trigonometry-le-fig-21-bd-=-ab-ad-and-in-the-second-bd-=-ad-abbut-in-both-cases-bd2-=-ab2-ad2-2ab-adto-both-sides-of-this-equation-add-cd2-then-bd2-cd2-=-ab2-ad2-cd2-2ab-adbut-bd2-cd2-=-bc2-ad2-f-cd2-=-ac2and-ad-=-ac-cos-a-c2-=-ab2-zc2-245-zc-cos-aor-a2-=-b2-f-c2-26c-cos-j-in-both-of-these-cases-the-side-a-is-opposite-an-acute-angleto-prove-the-same-thing-for-a-side-opposite-to-an-obtuseangle-we-have-in-the-second-triangle-fig-21-ad-=-ab-bd-ad2-=-ab2-bd2-f-2ab-bd-74-plane-trigonometry-ad-2CE0H3A.jpg)